Motion In One Dimension | Motion In Straight Line | Free MCQ Test - 01 (with Solutions) | CBSE, ICSE, ISC, IIT JEE, NEET, CET, KVPY, CUET, BITSAT, | Exam Preparation 2024

Question 1: Which of the following quantities can be zero when an object is in motion?
A) Displacement
B) Distance
C) Speed
D) Acceleration
Explanation: Displacement is the shortest distance between the initial and final positions of an object. If an object returns to its starting point, its displacement is zero, even though the distance traveled is not.

Question 2: A car moves along a straight road with a constant acceleration. If its initial velocity is 5 m/s and its acceleration is 2 m/s², what will be its velocity after 3 seconds?
A) 11 m/s
B) 7 m/s
C) 6 m/s
D) 12 m/s
Explanation: Use v = u + at.

Question 3: The area under the velocity-time graph represents which of the following physical quantities?
A) Acceleration
B) Force
C)Speed
D)Displacement
Explanation: The area under the velocity-time graph represents the displacement of an object. This is because displacement is the integral of velocity with respect to time.
Question 4: A particle moves in a straight line with uniform acceleration. Its initial velocity is 10 m/s, and its velocity after 5 seconds is 20 m/s. What is the acceleration of particle
A) 2 m/s²
B) 3 m/s²
C) 4 m/s²
D) 1 m/s²
Explanation: Use V= u + at .
Question 5: If an object is thrown upwards with an initial velocity of 15 m/s, what is its velocity after 2 seconds?
A) 5 m/s upward
B) 5 m/s downward
C) 10 m/s upward
D) 10 m/s downward
Explanation: Use v=u+at. Take a =-g. Because velocity of obejct is going to decrease so there will be deaceleration. And The negative sign indicates that the object is moving in the opposite direction to the initial velocity (i.e., downward), so the answer is 5m/s upward.

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