Answer: B) 19.6 m/s
2
Solution:
We know that the acceleration due to gravity \( g \) is given by:
\[
g = \frac{4}{3} \pi G R \rho
\]
where:
- \( G \) = Gravitational constant
- \( R \) = Radius of the Earth
- \( \rho \) = Density of the Earth
From the equation, \( g \propto \rho \) (when \( R \) is constant).
If the density is doubled, the new acceleration due to gravity \( g' \) will be:
\[
g' = 2g
\]
Substitute \( g = 9.8 \, \text{m/s}^2 \):
\[
g' = 2 \times 9.8 = 19.6 \, \text{m/s}^2
\]
Final Answer: The new acceleration due to gravity is 19.6 m/s2.
.png)
0 Comments