In the circuit shown, the switch S is connected to position 2 for a long time and then joined to position 1. The total heat produced in resistance R1

In the circuit shown, the switch \( S \) is connected to position 2 for a long time and then joined to position 1. The total heat produced in resistance \( R_1 \) is:

A) \( \frac{L}{R_2} \)
B) \( \frac{E^2L}{2R_1R_2} \)
C) \( \frac{E^2L}{2R^2_2} \)
D) \( \frac{(R_1+R_2)^2E^2}{2R_1R_2L} \)

Answer: C) \( \frac{E^2L}{2R^2_2} \)

Solution:

When the switch is at position 2 for a long time, the current through the inductor reaches its maximum value, given by:

\[ i = \frac{E}{R_2} \]

The energy stored in the inductor is:

\[ U_B = \frac{1}{2} L i^2 = \frac{1}{2} L \left( \frac{E}{R_2} \right)^2 = \frac{E^2L}{2R_2^2} \]

When the switch is moved to position 1, this stored energy is completely dissipated as heat in resistance \( R_1 \):

\[ \text{Heat dissipated} = \frac{E^2L}{2R^2_2} \]

Final Answer:

• The total heat produced in C) \( \frac{E^2L}{2R^2_2} \).

MCQ On Motion In Plane | Newton's Laws Of Motion | CBSE, IIT JEE, NEET, CET | Physics PYQ

WhatsApp Group Join Now

Telegram Group Join Now

>In the circuit shown, the switch \( S \) is connected to position 2 for a long time and then joined to position 1. The total heat produced in resistance R_1