Oscillation mcq test with answers
Time Left: 45:00
Total Marks: 160, Obtained Marks: 0
1. Which of the following is an example of oscillatory motion?
A. Motion of the moon around the earth
B. Uniform circular motion
C. Vibrations of a tuning fork
D. Motion of electrons around the nucleus
Explanation:
Oscillatory motion is a periodic motion where the object moves to and fro along the same path. Vibrations of a tuning fork are an example of oscillatory motion, as the prongs move back and forth about their mean position.
Therefore, the correct answer is: C. Vibrations of a tuning fork
Oscillatory motion is a periodic motion where the object moves to and fro along the same path. Vibrations of a tuning fork are an example of oscillatory motion, as the prongs move back and forth about their mean position.
Therefore, the correct answer is: C. Vibrations of a tuning fork
2. What is the defining characteristic of linear simple harmonic motion (S.H.M.)?
A. Motion along a circular path
B. Force is proportional to displacement and directed towards the mean position
C. Constant velocity during motion
D. Motion is always in one direction
Explanation:
In linear simple harmonic motion (S.H.M.), the restoring force (or acceleration) is always proportional to the displacement and directed towards the mean position. This characteristic ensures oscillatory motion.
Therefore, the correct answer is: B. Force is proportional to displacement and directed towards the mean position
In linear simple harmonic motion (S.H.M.), the restoring force (or acceleration) is always proportional to the displacement and directed towards the mean position. This characteristic ensures oscillatory motion.
Therefore, the correct answer is: B. Force is proportional to displacement and directed towards the mean position
3. Which of the following motions is periodic but not oscillatory?
A. Vibrations of a spring
B. Motion of the moon around the earth
C. Swinging of a pendulum
D. Up and down motion of a sewing machine needle
Explanation:
Periodic motion repeats itself after a fixed interval of time. However, oscillatory motion involves to-and-fro movement along the same path. The motion of the moon around the earth is periodic but not oscillatory.
Therefore, the correct answer is: B. Motion of the moon around the earth
Periodic motion repeats itself after a fixed interval of time. However, oscillatory motion involves to-and-fro movement along the same path. The motion of the moon around the earth is periodic but not oscillatory.
Therefore, the correct answer is: B. Motion of the moon around the earth
4. What is the restoring force in linear S.H.M. proportional to?
A. Velocity of the object
B. Mass of the object
C. Displacement from the mean position
D. Time period of oscillation
Explanation:
In linear S.H.M., the restoring force is directly proportional to the displacement of the object from the mean position and acts in the opposite direction.
Therefore, the correct answer is: C. Displacement from the mean position
In linear S.H.M., the restoring force is directly proportional to the displacement of the object from the mean position and acts in the opposite direction.
Therefore, the correct answer is: C. Displacement from the mean position
5. Which of the following best describes simple harmonic motion (S.H.M.)?
A. A periodic motion with restoring force proportional to displacement
B. A motion that is always uniform
C. A motion with constant acceleration
D. A non-repeating motion
Explanation:
Simple harmonic motion is a type of oscillatory motion where the restoring force is proportional to the displacement and directed towards the mean position.
Therefore, the correct answer is: A. A periodic motion with restoring force proportional to displacement
Simple harmonic motion is a type of oscillatory motion where the restoring force is proportional to the displacement and directed towards the mean position.
Therefore, the correct answer is: A. A periodic motion with restoring force proportional to displacement
6. What is the total energy in simple harmonic motion (S.H.M.) proportional to?
A. Square of the amplitude
B. Square of the displacement
C. Frequency of oscillation
D. Square of the velocity
Explanation:
The total energy in simple harmonic motion (S.H.M.) is proportional to the square of the amplitude. It remains constant as it alternates between potential and kinetic energy.
Therefore, the correct answer is: A. Square of the amplitude
The total energy in simple harmonic motion (S.H.M.) is proportional to the square of the amplitude. It remains constant as it alternates between potential and kinetic energy.
Therefore, the correct answer is: A. Square of the amplitude
7. Which quantity remains constant in simple harmonic motion (S.H.M.)?
A. Kinetic energy
B. Potential energy
C. Total mechanical energy
D. Acceleration
Explanation:
In simple harmonic motion (S.H.M.), the total mechanical energy, which is the sum of potential and kinetic energy, remains constant as energy continuously transforms between these two forms.
Therefore, the correct answer is: C. Total mechanical energy
In simple harmonic motion (S.H.M.), the total mechanical energy, which is the sum of potential and kinetic energy, remains constant as energy continuously transforms between these two forms.
Therefore, the correct answer is: C. Total mechanical energy
8. The time period of a simple pendulum depends on:
A. Length of the pendulum
B. Mass of the bob
C. Amplitude of oscillation
D. Gravitational constant
Explanation:
The time period of a simple pendulum is directly proportional to the square root of its length and inversely proportional to the square root of gravitational acceleration. It is independent of the mass of the bob and the amplitude for small oscillations.
Therefore, the correct answer is: A. Length of the pendulum
The time period of a simple pendulum is directly proportional to the square root of its length and inversely proportional to the square root of gravitational acceleration. It is independent of the mass of the bob and the amplitude for small oscillations.
Therefore, the correct answer is: A. Length of the pendulum
9. What happens to the time period of a pendulum when the length is quadrupled?
A. Remains the same
B. Doubles
C. Increases by a factor of 2
D. Reduces by half
Explanation:
The time period \(T\) of a pendulum is proportional to the square root of its length (\(T \propto \sqrt{L}\)). If the length is quadrupled, the time period doubles.
Therefore, the correct answer is: C. Increases by a factor of 2
The time period \(T\) of a pendulum is proportional to the square root of its length (\(T \propto \sqrt{L}\)). If the length is quadrupled, the time period doubles.
Therefore, the correct answer is: C. Increases by a factor of 2
10. Which of the following describes resonance?
A. Decrease in amplitude at specific frequencies
B. Maximum amplitude at natural frequency
C. Absence of oscillations
D. Constant phase difference between two waves
Explanation:
Resonance occurs when a system is driven at its natural frequency, resulting in maximum amplitude of oscillations.
Therefore, the correct answer is: B. Maximum amplitude at natural frequency
Resonance occurs when a system is driven at its natural frequency, resulting in maximum amplitude of oscillations.
Therefore, the correct answer is: B. Maximum amplitude at natural frequency
11. What is the phase difference between displacement and acceleration in simple harmonic motion (S.H.M.)?
A. π radians
B. 0 radians
C. π/2 radians
D. 2Ï€ radians
Explanation:
In S.H.M., acceleration is always opposite to the displacement and proportional to it. This leads to a phase difference of π radians.
Therefore, the correct answer is: A. π radians
In S.H.M., acceleration is always opposite to the displacement and proportional to it. This leads to a phase difference of π radians.
Therefore, the correct answer is: A. π radians
12. What happens to the time period of a pendulum when its length is doubled?
A. It remains the same
B. It becomes half
C. It decreases by a factor of √2
D. It increases by a factor of √2
Explanation:
The time period of a pendulum is given by \( T = 2\pi \sqrt{\frac{L}{g}} \). When the length \( L \) is doubled, \( T \) increases by a factor of \( \sqrt{2} \).
Therefore, the correct answer is: D. It increases by a factor of √2
The time period of a pendulum is given by \( T = 2\pi \sqrt{\frac{L}{g}} \). When the length \( L \) is doubled, \( T \) increases by a factor of \( \sqrt{2} \).
Therefore, the correct answer is: D. It increases by a factor of √2
13. What is the energy distribution at the mean position of a particle in S.H.M.?
A. Entirely potential energy
B. Entirely kinetic energy
C. Equal kinetic and potential energy
D. No energy
Explanation:
At the mean position, the displacement of the particle is zero, and its velocity is maximum, resulting in the energy being entirely kinetic.
Therefore, the correct answer is: B. Entirely kinetic energy
At the mean position, the displacement of the particle is zero, and its velocity is maximum, resulting in the energy being entirely kinetic.
Therefore, the correct answer is: B. Entirely kinetic energy
14. If the amplitude of S.H.M. is doubled, what happens to the total energy?
A. Remains the same
B. Increases four times
C. Doubles
D. Decreases by half
Explanation:
Total energy in S.H.M. is proportional to the square of the amplitude, \( E \propto A^2 \). Doubling the amplitude results in energy increasing four times.
Therefore, the correct answer is: B. Increases four times
Total energy in S.H.M. is proportional to the square of the amplitude, \( E \propto A^2 \). Doubling the amplitude results in energy increasing four times.
Therefore, the correct answer is: B. Increases four times
15. Which of the following represents the velocity equation in S.H.M.?
A. \( v = A \cos(\omega t) \)
B. \( v = A \sin(\omega t) \)
C. \( v = \omega \sqrt{A^2 - x^2} \)
D. \( v = \omega^2 x \)
Explanation:
The velocity in S.H.M. is given by \( v = \omega \sqrt{A^2 - x^2} \), where \( \omega \) is the angular frequency and \( A \) is the amplitude.
Therefore, the correct answer is: C. \( v = \omega \sqrt{A^2 - x^2} \)
The velocity in S.H.M. is given by \( v = \omega \sqrt{A^2 - x^2} \), where \( \omega \) is the angular frequency and \( A \) is the amplitude.
Therefore, the correct answer is: C. \( v = \omega \sqrt{A^2 - x^2} \)
16. In simple harmonic motion, the phase angle of the particle at the mean position is:
A. 0°
B. 90°
C. 180°
D. 270°
Explanation:
In simple harmonic motion, the phase angle at the mean position is 0°, as the displacement is maximum at this point and the particle is at its equilibrium position.
Therefore, the correct answer is: A. 0°
In simple harmonic motion, the phase angle at the mean position is 0°, as the displacement is maximum at this point and the particle is at its equilibrium position.
Therefore, the correct answer is: A. 0°
17. The total energy of a particle performing simple harmonic motion is:
A. Constant throughout the motion
B. Maximum at the extreme positions
C. Zero at the mean position
D. Maximum at the mean position
Explanation:
The total energy in simple harmonic motion is constant throughout the motion, as it is the sum of the potential energy and kinetic energy, both of which vary in such a way that their total remains constant.
Therefore, the correct answer is: A. Constant throughout the motion
The total energy in simple harmonic motion is constant throughout the motion, as it is the sum of the potential energy and kinetic energy, both of which vary in such a way that their total remains constant.
Therefore, the correct answer is: A. Constant throughout the motion
18. The displacement of a particle performing simple harmonic motion is given by x = A cos(ωt). The velocity at time t is:
A. \( v = A\omega \cos(\omega t) \)
B. \( v = A\omega \sin(\omega t) \)
C. \( v = -A\omega \sin(\omega t) \)
D. \( v = A\omega \cos(\omega t) \)
Explanation:
The velocity in simple harmonic motion is given by \( v = -A\omega \sin(\omega t) \), where \( A \) is the amplitude and \( \omega \) is the angular frequency.
Therefore, the correct answer is: C. \( v = -A\omega \sin(\omega t) \)
The velocity in simple harmonic motion is given by \( v = -A\omega \sin(\omega t) \), where \( A \) is the amplitude and \( \omega \) is the angular frequency.
Therefore, the correct answer is: C. \( v = -A\omega \sin(\omega t) \)
19. The period of a simple pendulum depends on:
A. Mass of the pendulum
B. Amplitude of oscillation
C. Acceleration due to gravity
D. All of the above
Explanation:
The period of a simple pendulum depends only on the length of the pendulum and the acceleration due to gravity, not on its mass or amplitude for small oscillations.
Therefore, the correct answer is: C. Acceleration due to gravity
The period of a simple pendulum depends only on the length of the pendulum and the acceleration due to gravity, not on its mass or amplitude for small oscillations.
Therefore, the correct answer is: C. Acceleration due to gravity
20. A body performs angular simple harmonic motion. The restoring torque acting on it is proportional to:
A. Angular displacement
B. Angular velocity
C. Moment of inertia
D. Angular acceleration
Explanation:
In angular simple harmonic motion, the restoring torque is proportional to the angular displacement, similar to the force in linear simple harmonic motion.
Therefore, the correct answer is: A. Angular displacement
In angular simple harmonic motion, the restoring torque is proportional to the angular displacement, similar to the force in linear simple harmonic motion.
Therefore, the correct answer is: A. Angular displacement
21. The frequency of oscillation of a mass-spring system is independent of:
A. Mass of the object
B. Amplitude of oscillation
C. Spring constant
D. Acceleration due to gravity
Explanation:
The frequency of a mass-spring system depends on the mass of the object and the spring constant. It is independent of the amplitude of oscillation.
Therefore, the correct answer is: B. Amplitude of oscillation
The frequency of a mass-spring system depends on the mass of the object and the spring constant. It is independent of the amplitude of oscillation.
Therefore, the correct answer is: B. Amplitude of oscillation
22. In simple harmonic motion, the maximum acceleration occurs at:
A. The mean position
B. The extreme positions
C. The quarter of the period
D. The mid-point of the motion
Explanation:
The maximum acceleration in simple harmonic motion occurs at the extreme positions, where the displacement is maximum.
Therefore, the correct answer is: B. The extreme positions
The maximum acceleration in simple harmonic motion occurs at the extreme positions, where the displacement is maximum.
Therefore, the correct answer is: B. The extreme positions
23. The period of a simple pendulum is doubled when the length of the pendulum is:
A. Doubled
B. Quadrupled
C. Tripled
D. Increased by a factor of 8
Explanation:
The period \( T \) of a simple pendulum is given by \( T = 2\pi\sqrt{\frac{L}{g}} \). If the length is quadrupled, the period will double.
Therefore, the correct answer is: B. Quadrupled
The period \( T \) of a simple pendulum is given by \( T = 2\pi\sqrt{\frac{L}{g}} \). If the length is quadrupled, the period will double.
Therefore, the correct answer is: B. Quadrupled
24. In simple harmonic motion, the displacement, velocity, and acceleration are:
A. In phase with each other
B. 90° out of phase with each other
C. 180° out of phase with each other
D. None of the above
Explanation:
In simple harmonic motion, the displacement and velocity are 90° out of phase, and the velocity and acceleration are also 180° out of phase.
Therefore, the correct answer is: B. 90° out of phase with each other
In simple harmonic motion, the displacement and velocity are 90° out of phase, and the velocity and acceleration are also 180° out of phase.
Therefore, the correct answer is: B. 90° out of phase with each other
25. The total energy of a particle performing simple harmonic motion is given by:
A. \( E = \frac{1}{2} m \omega^2 A^2 \)
B. \( E = \frac{1}{2} k A^2 \)
C. \( E = \frac{1}{2} m A^2 \)
D. \( E = \frac{1}{2} m \omega^2 \)
Explanation:
The total energy in simple harmonic motion is given by \( E = \frac{1}{2} k A^2 \), where \( k \) is the spring constant and \( A \) is the amplitude.
Therefore, the correct answer is: B. \( E = \frac{1}{2} k A^2 \)
The total energy in simple harmonic motion is given by \( E = \frac{1}{2} k A^2 \), where \( k \) is the spring constant and \( A \) is the amplitude.
Therefore, the correct answer is: B. \( E = \frac{1}{2} k A^2 \)
26. The time period of a mass-spring system is independent of:
A. Mass of the object
B. Spring constant
C. Amplitude of oscillation
D. Both A and B
Explanation:
The time period of a mass-spring system depends on the mass of the object and the spring constant but is independent of the amplitude of oscillation.
Therefore, the correct answer is: C. Amplitude of oscillation
The time period of a mass-spring system depends on the mass of the object and the spring constant but is independent of the amplitude of oscillation.
Therefore, the correct answer is: C. Amplitude of oscillation
27. In simple harmonic motion, the total mechanical energy is:
A. Constant
B. Maximum at the mean position
C. Zero at the extreme positions
D. Dependent on the amplitude
Explanation:
The total mechanical energy in simple harmonic motion is constant throughout the motion, being the sum of kinetic and potential energy.
Therefore, the correct answer is: A. Constant
The total mechanical energy in simple harmonic motion is constant throughout the motion, being the sum of kinetic and potential energy.
Therefore, the correct answer is: A. Constant
28. The frequency of a simple pendulum depends on:
A. Mass of the bob
B. Length of the pendulum
C. Amplitude of oscillation
D. Both A and C
Explanation:
The frequency of a simple pendulum depends on the length of the pendulum and the acceleration due to gravity. It is independent of the mass of the bob and amplitude for small oscillations.
Therefore, the correct answer is: B. Length of the pendulum
The frequency of a simple pendulum depends on the length of the pendulum and the acceleration due to gravity. It is independent of the mass of the bob and amplitude for small oscillations.
Therefore, the correct answer is: B. Length of the pendulum
29. The phase of a particle performing simple harmonic motion is:
A. Always zero
B. Always 90°
C. Varies with time
D. Constant throughout
Explanation:
The phase of a particle performing simple harmonic motion varies with time and is given by \( \phi = \omega t + \phi_0 \), where \( \phi_0 \) is the initial phase.
Therefore, the correct answer is: C. Varies with time
The phase of a particle performing simple harmonic motion varies with time and is given by \( \phi = \omega t + \phi_0 \), where \( \phi_0 \) is the initial phase.
Therefore, the correct answer is: C. Varies with time
30. In simple harmonic motion, the maximum velocity is given by:
A. \( v_{\text{max}} = A\omega \)
B. \( v_{\text{max}} = A\omega^2 \)
C. \( v_{\text{max}} = \omega^2 A \)
D. \( v_{\text{max}} = \frac{A}{\omega} \)
Explanation:
The maximum velocity in simple harmonic motion is given by \( v_{\text{max}} = A\omega \), where \( A \) is the amplitude and \( \omega \) is the angular frequency.
Therefore, the correct answer is: A. \( v_{\text{max}} = A\omega \)
The maximum velocity in simple harmonic motion is given by \( v_{\text{max}} = A\omega \), where \( A \) is the amplitude and \( \omega \) is the angular frequency.
Therefore, the correct answer is: A. \( v_{\text{max}} = A\omega \)
31. The oscillation of a body is described by the equation \( x = A \cos(\omega t + \phi) \). The quantity \( \phi \) represents:
A. The amplitude of oscillation
B. The phase constant
C. The angular frequency
D. The time period
Explanation:
In the equation \( x = A \cos(\omega t + \phi) \), the term \( \phi \) represents the phase constant, which determines the initial position of the oscillating body.
Therefore, the correct answer is: B. The phase constant
In the equation \( x = A \cos(\omega t + \phi) \), the term \( \phi \) represents the phase constant, which determines the initial position of the oscillating body.
Therefore, the correct answer is: B. The phase constant
32. The frequency of a simple harmonic oscillator is increased by increasing:
A. The spring constant
B. The amplitude
C. The mass of the object
D. The displacement from equilibrium
Explanation:
The frequency \( f \) of a simple harmonic oscillator is given by \( f = \frac{1}{2\pi} \sqrt{\frac{k}{m}} \), where \( k \) is the spring constant and \( m \) is the mass. The frequency increases when the spring constant increases.
Therefore, the correct answer is: A. The spring constant
The frequency \( f \) of a simple harmonic oscillator is given by \( f = \frac{1}{2\pi} \sqrt{\frac{k}{m}} \), where \( k \) is the spring constant and \( m \) is the mass. The frequency increases when the spring constant increases.
Therefore, the correct answer is: A. The spring constant
33. In a simple harmonic oscillator, when the displacement is zero, the kinetic energy is:
A. Maximum
B. Zero
C. Half of the total energy
D. Equal to potential energy
Explanation:
When the displacement is zero, the object is at the equilibrium position, and all the energy is in the form of kinetic energy. However, at the mean position, the displacement is zero, and kinetic energy is at a maximum, not zero. Therefore, the kinetic energy is not zero when displacement is zero.
Therefore, the correct answer is: B. Zero
When the displacement is zero, the object is at the equilibrium position, and all the energy is in the form of kinetic energy. However, at the mean position, the displacement is zero, and kinetic energy is at a maximum, not zero. Therefore, the kinetic energy is not zero when displacement is zero.
Therefore, the correct answer is: B. Zero
34. The total mechanical energy of an oscillator performing simple harmonic motion is:
A. The sum of kinetic and potential energies
B. Zero
C. Constant
D. Varies with time
Explanation:
In simple harmonic motion, the total mechanical energy is the sum of kinetic and potential energy, and it remains constant throughout the motion.
Therefore, the correct answer is: A. The sum of kinetic and potential energies
In simple harmonic motion, the total mechanical energy is the sum of kinetic and potential energy, and it remains constant throughout the motion.
Therefore, the correct answer is: A. The sum of kinetic and potential energies
35. In a simple harmonic oscillator, the displacement at any point in time is given by \( x = A \cos(\omega t) \). The angular frequency \( \omega \) is related to:
A. Only the amplitude
B. The spring constant and mass
C. The amplitude and time period
D. Only the time period
Explanation:
The angular frequency \( \omega \) is related to the spring constant \( k \) and mass \( m \) as \( \omega = \sqrt{\frac{k}{m}} \).
Therefore, the correct answer is: B. The spring constant and mass
The angular frequency \( \omega \) is related to the spring constant \( k \) and mass \( m \) as \( \omega = \sqrt{\frac{k}{m}} \).
Therefore, the correct answer is: B. The spring constant and mass
36. The amplitude of oscillation in a simple harmonic oscillator is doubled. What happens to the maximum velocity?
A. It remains the same
B. It is doubled
C. It is quadrupled
D. It is halved
Explanation:
The maximum velocity \( v_{\text{max}} \) is given by \( v_{\text{max}} = A\omega \). When the amplitude \( A \) is doubled, the maximum velocity also doubles.
Therefore, the correct answer is: B. It is doubled
The maximum velocity \( v_{\text{max}} \) is given by \( v_{\text{max}} = A\omega \). When the amplitude \( A \) is doubled, the maximum velocity also doubles.
Therefore, the correct answer is: B. It is doubled
37. A body executes simple harmonic motion with amplitude \( A \) and time period \( T \). The maximum acceleration is:
A. \( A/T \)
B. \( \frac{A}{T^2} \)
C. \( A\omega^2 \)
D. \( \omega^2/A \)
Explanation:
The maximum acceleration \( a_{\text{max}} \) in simple harmonic motion is given by \( a_{\text{max}} = A\omega^2 \), where \( \omega \) is the angular frequency.
Therefore, the correct answer is: C. \( A\omega^2 \)
The maximum acceleration \( a_{\text{max}} \) in simple harmonic motion is given by \( a_{\text{max}} = A\omega^2 \), where \( \omega \) is the angular frequency.
Therefore, the correct answer is: C. \( A\omega^2 \)
38. The energy of a simple harmonic oscillator is completely potential at:
A. The mean position
B. The extreme positions
C. The midpoint of the oscillation
D. The equilibrium point
Explanation:
The energy of a simple harmonic oscillator is completely potential at the extreme positions, where the velocity is zero and all the energy is stored as potential energy.
Therefore, the correct answer is: B. The extreme positions
The energy of a simple harmonic oscillator is completely potential at the extreme positions, where the velocity is zero and all the energy is stored as potential energy.
Therefore, the correct answer is: B. The extreme positions
39. The time period of a simple pendulum depends on which of the following factors?
A. Mass of the bob
B. Length of the pendulum
C. Shape of the bob
D. Amplitude of oscillation
Explanation:
The time period \( T \) of a simple pendulum is given by \( T = 2\pi \sqrt{\frac{L}{g}} \), where \( L \) is the length of the pendulum and \( g \) is the acceleration due to gravity. It is independent of the mass and amplitude for small oscillations.
Therefore, the correct answer is: B. Length of the pendulum
The time period \( T \) of a simple pendulum is given by \( T = 2\pi \sqrt{\frac{L}{g}} \), where \( L \) is the length of the pendulum and \( g \) is the acceleration due to gravity. It is independent of the mass and amplitude for small oscillations.
Therefore, the correct answer is: B. Length of the pendulum
40. In a damped harmonic oscillator, the amplitude of oscillation:
A. Increases with time
B. Decreases with time
C. Remains constant
D. Is independent of damping
Explanation:
In a damped harmonic oscillator, the amplitude decreases with time due to the dissipative force (e.g., friction or air resistance).
Therefore, the correct answer is: B. Decreases with time
In a damped harmonic oscillator, the amplitude decreases with time due to the dissipative force (e.g., friction or air resistance).
Therefore, the correct answer is: B. Decreases with time
.png)
0 Comments