Electron Velocity in Crossed Fields (1996)
Question: Electrons move undeflected through perpendicular \( E = 20 \, \text{V/m} \) and \( B = 0.5 \, \text{T} \). Their velocity is:
(a) 8 m/s
(b) 5.5 m/s
(c) 20 m/s
(d) 40 m/s
Solution
Step 1: Force Balance
For undeflected motion:
\[
qE = qvB \implies v = \frac{E}{B}
\]
Step 2: Calculation
\[
v = \frac{20 \, \text{V/m}}{0.5 \, \text{T}} = 40 \, \text{m/s}
\]
Answer: Option (d) \( 40 \, \text{m/s} \) is correct.
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