Force Superposition in Charge Interactions
A charge \( q_{1} \) exerts a force on a second charge \( q_{2} \) according to Coulomb's law. If a third charge \( q_{3} \) is brought near, what happens to:
(i) The force that \( q_{1} \) exerts on \( q_{2} \), and (ii) the net force on \( q_{2} \)?
Select the correct option:
Detailed Explanation
According to Coulomb’s law, the force between two charges is given by: \[ F = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}. \]
The key principle here is superposition: the force that \( q_{1} \) exerts on \( q_{2} \) depends only on these two charges and their distance. This force is unaffected by the presence of a third charge.
However, when a third charge \( q_{3} \) is brought near, it exerts its own force on \( q_{2} \). The net force on \( q_{2} \) becomes the vector sum of the force from \( q_{1} \) and the force from \( q_{3} \). Depending on the magnitude, direction, and sign of \( q_{3} \), the net force on \( q_{2} \) may increase or decrease, or even change direction.
Therefore, while the force from \( q_{1} \) on \( q_{2} \) remains unchanged, the net force on \( q_{2} \) may either increase or decrease. This corresponds to option (C).
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