Magnetic Force and Angle Dependency
Question: When a charged particle moving with velocity \( \vec{v} \) is subjected to a magnetic field of induction \( \vec{B} \), the force on it is non-zero. This implies that:
Detailed Step-by-Step Explanation
Step 1: Magnetic Force Formula
The magnetic force \( \vec{F} \) on a charged particle moving with velocity \( \vec{v} \) in a magnetic field \( \vec{B} \) is given by the Lorentz force law:
\[
\vec{F} = q (\vec{v} \times \vec{B})
\]
where \( q \) is the charge.
Step 2: Dependency on the Angle
The magnitude of the force is:
\[
F = qvB \sin \theta,
\]
where \( \theta \) is the angle between \( \vec{v} \) and \( \vec{B} \).
Step 3: Condition for a Non-Zero Force
For the force \( F \) to be non-zero, the term \( \sin \theta \) must be non-zero. This means:
\[
\sin \theta \neq 0.
\]
The sine of an angle is zero when the angle is \( 0^\circ \) or \( 180^\circ \).
Therefore, if the force is non-zero, the angle \( \theta \) must be any value other than \( 0^\circ \) or \( 180^\circ \).
Final Answer: The angle between \( \vec{v} \) and \( \vec{B} \) can have any value other than \( 0^\circ \) and \( 180^\circ \), which corresponds to option (d).
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